4x^2+4x+1=81

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Solution for 4x^2+4x+1=81 equation:


Simplifying
4x2 + 4x + 1 = 81

Reorder the terms:
1 + 4x + 4x2 = 81

Solving
1 + 4x + 4x2 = 81

Solving for variable 'x'.

Reorder the terms:
1 + -81 + 4x + 4x2 = 81 + -81

Combine like terms: 1 + -81 = -80
-80 + 4x + 4x2 = 81 + -81

Combine like terms: 81 + -81 = 0
-80 + 4x + 4x2 = 0

Factor out the Greatest Common Factor (GCF), '4'.
4(-20 + x + x2) = 0

Factor a trinomial.
4((-5 + -1x)(4 + -1x)) = 0

Ignore the factor 4.

Subproblem 1

Set the factor '(-5 + -1x)' equal to zero and attempt to solve: Simplifying -5 + -1x = 0 Solving -5 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '5' to each side of the equation. -5 + 5 + -1x = 0 + 5 Combine like terms: -5 + 5 = 0 0 + -1x = 0 + 5 -1x = 0 + 5 Combine like terms: 0 + 5 = 5 -1x = 5 Divide each side by '-1'. x = -5 Simplifying x = -5

Subproblem 2

Set the factor '(4 + -1x)' equal to zero and attempt to solve: Simplifying 4 + -1x = 0 Solving 4 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1x = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1x = 0 + -4 -1x = 0 + -4 Combine like terms: 0 + -4 = -4 -1x = -4 Divide each side by '-1'. x = 4 Simplifying x = 4

Solution

x = {-5, 4}

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